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how often should i water my vegetable garden?

1 inch of water a week if they are up and growing. Plants like moist soil but they do not like to be so moist that the roots rot

where do they keep the ace of spades in the garden centre?

in with the tools for diamond mining, to the right of the golf clubs and opposite the sheeps hearts

how do you keep the birds out of your garden?

You will probably have to cover it with some kind of netting or maybe chicken wire

Is today (April 5th, 2020) a good time to start growing peas and other items in your garden if you live in Utah or a nearby state? What will happen if it snows later since snow has been known to come as late as May?

Too early. Down East the rule is Mother's Day, but at altitude (I live in Denver now), that might be a week or 10 days too early, because frosts and snows can come until the 3rd week of May. Start them in your kitchen window, e.g., right now, but do not put them in the ground until at least mid-May

where can I find annual sales of garden watering products?

Local stores do not always have the highest quality sprinkler parts. You do not want to buy stuff that's just gonna fall apart in a year, even if it is on sale. Try and go for the Hunter brand- best stuff on the market.

How do I stop my garden gnomes from misbehaving?

how old are you, 9..10?? how many times are you gonna ask this, geez smash them in a million pieces.

What kinds of plants can I use for our school's botanical garden?

So Adam and Eve come 2nd and third to cats did they... so as that's why the egyptians believed them to be gods... it extremely is all so sparkling now... God, get a extremely is spelt you backwards

Do you think we could handle this as a new garden?

Yeah, it sounds pretty do-able. I would make sure to have plenty of room for the watermelon and use six foot tall lattices for the cucumbers. It keeps them off the ground so they are even colored, clean of rotting sides and straight. I would plant a pickling variety and a salad (asian is real good with tiny seeds) variety. Tomatoes and peppers need full sun and are in the same family so you should do a second bed to rotate them to every other year and put something like onions, carrots, beets, swiss chard, kohlrabi or beans in that one. All but the carrots in that list are really easy. The most important tip I could give otherwise is COMPOST COMPOST and more COMPOST! Good soil means good plants.

how do you prepare a garden plot for spring planting in the fall?

spade it up. rake out all the weeds and get them out of the space. Maybe get some cow manure and work it in to the soil so that it has plenty of time to break down over the winter months. and in the Spring spade it again, rake it out , and plant,.

I would like to get a rabbit but will it be safe in a hutch in the garden?

A nice secure hutch..with some wire fencing around the outside, make sure it is on solid ground as foxes will dig up the soil and get in that way. Personally my bunnies are outside in the run during the daytime and they come inside on a nighttime (In a fairly big rabbit box) That way they are warm and just for my peace of mind, too, especially as I live in the countryside.

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The sample cost is triple of the unit price.But we will return the extra once received your next order• RELATED QUESTIONAre multiple sets with decreasing weight and no rest between them a good idea?You will find that there are several options for programming (the combination and scheduling of exercises, sets, and reps that you do), and they all accomplish a set goal. Many successful programming incorporate the concept of As Many Reps As Possible (AMRAP), which only differs from going to failure by saving a rep in the tank.High volume assistance work like curls, leg presses, etc. is very beneficial for muscle size and joint health. Paul Carter suggests 5 sets of 8-12 for upper body assistance lifts or 5 sets of 12-15 for lower body assistance lifts. But he also has a program which has you going to failure, trying to beat your last week's number, and then following it with trying to get half the reps going to failure again. The high rep assistance work gets blood flowing through the joints and strengthens your tendons which helps remedy inflammation and prevent it.Another common approach is the pyramid approach which is something similar to what you described. You work up to a top set, and then back down. Here's some food for thought distilled from books from Jim Wendler, Paul Carter, and Mark Rippetoe:Remember that size is a result of the volume of work you put your muscles through. You should aim to get stronger, so that you have the ability to increase your volumeFind open sets in a normal spaceTo reduce notational clutter, let $F_1 = X setminus U_1$ and $F_2 = X setminus U_2$. You've chosen open sets $V_1,V_2$ such that $F_2 subseteq V_1 subseteq operatornameclV_1subseteq U_1$ and $F_1 subseteq V_2 subseteq operatornameclV_2subseteq U_2$, and you would like to show that $X = V_1 cup V_2$. Unfortunately, you can not guarantee this. Take $X$ to be $[0,1]$ with the usual topology, $U_1 = [0,1)$, and $U_2 = (0,1]$. Then $F_1 = 1$, $F_2 = 0$, and $V_1$ and $V_2$ could turn out to be $[0,1/4)$ and $(3/4,1]$, for instance. This shows that your idea wo not work as it stands.Notice that since $U_1 cup U_2 = X$, $F_1 cap F_2 = varnothing$. That is, $F_1$ and $F_2$ are disjoint closed sets in the normal space $X$. Therefore there are open sets $V_1,V_2$ such that $F_1 subseteq V_1$, $F_2 subseteq V_2$, and $operatornameclV_1 cap operatornameclV_2 = varnothing$. Let $W_1 = X setminus operatornameclV_1$ and $W_2 = X setminus operatornameclV_2$; clearly these are open sets and $W_1 cup W_2 = X$, so it only remains to show that $operatornameclW_1 subseteq U_1$ and $operatornameclW_2 subseteq U_2$, which is not too hard: clearly $X setminus V_1$ is a closed set containing $W_1$, so $operatornameclW_1 subseteq X setminus V_1 subseteq X setminus F_1 = U_1$, and a similar computation shows that $operatornameclW_2 subseteq U_2$.Examples of rare, meager and nonmeager sets in $mathbbR$Your first two examples are spot on. Actually, so is the third.The proof of this relies on the Baire Category Theorem, mentioned in the comments above. To see this, recall that any non-degenerate open interval $(a,b)$ is homeomorphic to the real line $mathbbR$. As $mathbbR$ is a complete metric space, it follows that $(a,b)$ is completely metrizable (of course, the usual metric is not complete on $(a,b)$, but some other metric — one derived from a homeomorphism from $mathbbR$ — makes it complete). Therefore $(a,b)$ is nonmeagre-in-itself by the Baire Category Theorem.If $(a,b) = bigcup_n Z_n$ where each $Z_n$ is nowhere dense in $mathbbR$, it would follow that each $Z_n$ is also nowhere dense in the subspace $(a,b)$, which would then contradict the fact that $(a,b)$ is nonmeagre-in-itself.A quick comment about your second example: It is good that you note that the singleton sets in $mathbbR$ are nowhere dense. For instance, $mathbbN$ is countable, but not meagre-in-itself, because $mathbbN$ is discrete (all subsets are open) and so the singleton sets are not nowhere dense in $mathbbN$. (Of course, $mathbbN$ is meagre in $mathbbR$.)Notation about sets and probabilityThe equation is true because the union of the sets on each side are equal. Using the fact that $X_textthin subseteq X$ and beginning with the union of the sets on the LHS:begineqnarray* (X_textthincap A);cup; (Xsetminus X_textthincap B) &=& (X_textthincap Asetminus B);cup; (X_textthincap Acap B) / && cup;;(Xsetminus X_textthincap Bsetminus A) ;cup; (Xsetminus X_textthincap Acap B) / && qquadqquadtext(splitting each of the two terms into two parts) /&& / &=& (X_textthincap Asetminus B);cup; (Xcap Acap B); cup;(Xsetminus X_textthincap Bsetminus A) / && qquadqquadtext(combining the second and fourth terms) / && / &=& textunion of the sets on the RHS. endeqnarray*A Venn diagram might help you visualise what is going on here.How do I determine the possible number of combinations of two ordered sets?You are talking about (resulting) tuples I presume (and not sets).If the sets are $S$ with $s$ elements and $T$ with $t$ elements, then the total possible tuples is $displaystyle st choose s$.Basically, you have $st$ slots and you pick the slots (say $s$) for one of the sets in $displaystyle st choose s$ ways. Once the slots are chosen, all the $st$ numbers can now be filled in only one way.So the total is $displaystyle st choose s$Counting sets by their connectednessI recently came up with a faster solution to this problem that reduces the recurrence dimension by 1.Let $T_r(n, m, c)$ represent the number we are looking for, ie. the number of ways to take $m$ subsets of $[n]$ such that each subset has size $r$, the subsets cover $[n]$, and their intersection graph has $c$ connected components. I made $r$ a subscript because it is held fixed throughout. The logic is similar to $T_n^c times ell$ in my answer above. Consider the connected component that covers the element "1" from the ground set. Suppose it consists of $s$ subsets and that it covers $k$ total elements. There are $binomn - 1k - 1$ ways to choose the covered elements which leads to the recurrence for $c > 1$. $$T_r(n, m, c) = sum_k sum_s binomn - 1k - 1 ; T_r(n!-!k, ,m!-!s,,c!-!1) ; T_r(k, s, 1) $$For connected graphs $c = 1$ we get the same restriction formula from before: all the possible graphs given $m$ minus those that do not cover $[n]$ minus those that have more than 1 connected component. $$ T_r(n, m, 1) ; = ; n choose r choose m ; - ; sum_k , , 1 T_r(n, m, c)$$IEnumerable and Predicate sets in .NETREVISED VERSION==========================================================================Previously: Countable and uncountable sets in .NET (clean version).Thesis There is a full featured support of countable sets in .NET: IEnumerable. What about uncountable sets; sets defined by predicate? How can they be manipulated and interact with IEnumerable? What is new? Operators has been unified:1) Implicit conversion defined:2) Operators redefined to ensure symmetry and simplicity:Solution Let's introduce two library classes: Universe and Set, where Universe is a factory of Sets and Sets are defined by predicate, condition like Func. Example:We define some basic calculus on sets:Intersection:Now, how to test the set (it is just a combined condition underneath, nothing else) - let's use intersection operator, as scalar value is just a set of one element:Actually, tests return Enumerable, which is truthy; it could be falsy if empty. We can iterate the result, getting 0 or 1 element.Union operator provides us with an another set:The most useful feature is an integration with IEnumerable. Let's have:We can inersect them:We can join them, so result will be another Set:We can even exclude set from enumeration getting an enumeration, or exclude enumeration from set - getting set as a result.Demo Let's define Customer, Order, Invoice to calculate discounts (full solution is available online to play with):Now helpers:Our discount rules are going to be:Let's test the sets:Library code:Told by Professor that this is PIE, but don't see how it's PIE. Help understanding what constitutes the sets, or alternative ways to solve?As usual gave an excellent answer. Here I "supplement" his answer by showing how all this maps to set theory, what the sets are, etc.PIE goes like this:$$|bigcup_i A_i| = sum_i |A_i| - sum_i Is there a term do refer to a “set of sets” in math, to distinguish set of regular math objet?The term "family" is used for sets of sets. This usage is most common when all the elements of the sets in the family are of the same kind (So in your examples $D = A,C = 1,2,3,3,5,6$ is a more typical example than say $A,B = 1,2,3,mathrmblue,mathrmwhite,mathrmred$). Wikipedia:Using mathematical induction to prove a generalized form of DeMorgan's Law for setsIt is not circular reasoning because they have already proven the DeMorgan's Law involving two sets, and they use that to help prove the Generalized DeMorgan's Law. Indeed, in the step you indicate where they use the DeMorgan's Law they apply it to two sets: $B$ and $A_k1$, so that is perfectly valid.Maybe you are worried about the fact that $B$ is defined as the intersection of $k$ sets $A_1$ through $A_k$? Well, first of all, that does not take away from the fact that $B$ is still one set, and second, they do not apply the DeMorgan's rule over those sets $A_1$ through $A_k$ at the time of that step ... They do that later using the inductive hypothesis.In short: DeMorgan's Law $ot =$ Generalized DeMorgan's LawWhy were equivalence classes named classes rather than sets?One detailed account of the history of equivalence relations and associated terminology is Equivalence: An Attempt at a History of the Idea by Ashgari largely based on Fowler's posts on the Historia Mathematica forum. The terminology was a long time in the making, with "equivalence relation" appearing much earlier than "equivalence class". Although neither the sources nor Ashgari directly answer why the choice of "class" was preferred there is one clue as to the possible reason. Even before "equivalence relation" was so named abstractly by Jourdain, a particular use of "equivalence" and its classes was prominent, and remained so for a while after. It is the equivalence of sets by equipotence or cardinality, the relation being existence of a bijective correspondence between them, introduced by Hume and popularized by Cantor. In this case, the equivalence classes (of all sets with the same cardinality) are not themselves sets. As this seemed to be the paradigmatic example, by the time abstract terminology was being established the authors might have favored a combination of words they were already used to hearing. And this way there was no need to explain that in the case of cardinality the "equivalence sets" are not sets.Von Neumann introduced the set/class distinction in set theory explicitly in 1925 (it became the basis of a set theory axiomatization NBG, alternative to classless ZFC), but in 1926 and 1929 he used the expression "equivalence class" in some algebraic contexts nonetheless. Aside from cardinality, there was some pre-existing terminology with "classes" in algebra, e.g. Weber introduced "class field" in 1891, see Miller's Earliest Known Uses, Jordan in a paper on group characters talked of "classes of conjugate substitutions" (to become conjugacy classes) in 1907. So it seems that the terminological transition from classes to sets only happened narrowly, where it mattered, and older terminology was generally preferred where it was already established. Here are some relevant passages from Ashgari:
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